Is this approach is correct?
But have you run my code?
Hi , is it freelancer work?
Are u open to relocate to Ahmedabad?
Can you please share the details?
Do you have any requirements in React js, Next js, Node js, DevOps and Angular?
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Is this approach is correct??
import java.util.*;
class Main {
static void checkArray(int a[], int b[], int n)
{
Set<Integer> hh = new HashSet<Integer>();
int operations = 0;
int i = 0;
for (i=0;i<n;i++){
operations = a[i]-b[i];
if(operations!=0){
hh.add(operations);
}
}
System.out.println(hh.size());
}
public static void main (String[] args)
{
int a[] = { 3, 7, 1, 4, 1, 2 };
int b[] = { 3, 7, 3, 6, 3, 3 };
int size = a.length;
checkArray(a, b, size);
}
}
This will give the count of all elements whose diff. is >0. i.e. for the sample input, you’ll get 4 as output, instead of 1.
The question is: How many operations are to be performed in order to make Array A[] same as Array B[]. And, the definition of an operation is: Add an (one unique) integer K into the subarray of the Array A[] (from left to right).
So, an operation is required only when the elements are different.
Therefore to count the no. of operations required, you just need to check how many unique integers are required to be added. In other words, find the count of unique differences.
For ex., in the input
int a[] = {3. 7, 1, 4, 1, 2}
int b[] = {3, 7, 3, 6, 3, 3}
the no. of elements that are diff. is 4 (1,4,1,2 from A[] & the corresponding in B[]). And, all of them have the same difference, respectively (i.e. 2). Therefore, we need to add only 2 to all the elements of array A[] to make it same as B[], Means the no. of unique differences is 2. Therefore, the no. of operations is 1.
If the input is like,
int a[] = {3. 7, 1, 4, 1, 2}
int b[] = {3, 7, 3, 5, 3, 3}
the no. of unique diff. would be 2 & therefore no. of operations will also be 2.
The question is: How many operations are to be performed in order to make Array A[] same as Array B[]. And, the definition of an operation is: Add an (one unique) integer K into the subarray of the Array A[] (from left to right).
So, an operation is required only when the elements are different.
Therefore to count the no. of operations required, you just need to check how many unique integers are required to be added. In other words, find the count of unique differences.
For ex., in the input
int a[] = {3. 7, 1, 4, 1, 2}
int b[] = {3, 7, 3, 6, 3, 3}
the no. of elements that are diff. is 4 (1,4,1,2 from A[] & the corresponding in B[]). And, all of them have the same difference, respectively (i.e. 2). Therefore, we need to add only 2 to all the elements of array A[] to make it same as B[], Means the no. of unique differences is 2. Therefore, the no. of operations is 1.
If the input is like,
int a[] = {3. 7, 1, 4, 1, 2}
int b[] = {3, 7, 3, 5, 3, 3}
the no. of unique diff. would be 2 & therefore no. of operations will also be 2.
But have you run my code??
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Hi , is it freelancer work?
I am looking for a job change.Have experience of 2.4 years in Java Development.
Please let me know if there are any openings for the same.
Are u open to relocate to Ahmedabad?
Hii, looking for fullstock Java Developers with experience of 4+years. Interested DM me.
Work from home only, contract basis it will be renewable based on your performance.
Can you please share the details?
I am looking for a job change.Have experience of 2.4 years in Java Development.
Please let me know if there are any openings for the same.
We are having opportunity for the same
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